What is the integral of 3/(x-3) ?

The integral of 3/(x-3) is 3ln|x-3|+C

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integral of 3/(x-3)

\int \frac{3}{x - 3} d x

3 ln ∣ x - 3 ∣ + C

Solution steps

\int \frac{3}{x - 3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int \frac{1}{x - 3} d x

Apply u-substitution

: \int \frac{1}{u} d u

= 3 \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= 3 ln ∣ u ∣

Substitute back

u = x - 3

= 3 ln ∣ x - 3 ∣

Add a constant to the solution

= 3 ln ∣ x - 3 ∣ + C

x^{2} - 10

ln (x^{4} + 2)

\frac{d y}{d x} = 2 y - x

n = 7 \sum \infty e^{7 - 2 n}

\frac{d}{d x} (\frac{15}{x} + \frac{225}{15 - x})