What is the solution for (dy)/(dx)= x/(y^2),y(2)=3 ?

The solution for (dy)/(dx)= x/(y^2),y(2)=3 is y=\sqrt[3]{(3x^2)/2+21}

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(dy)/(dx)= x/(y^2),y(2)=3

\frac{d y}{d x} = \frac{x}{y ^{2}}, y (2) = 3

y = 3 \frac{3 x ^{2}}{2} + 21

Solution steps

\frac{d y}{d x} = \frac{x}{y ^{2}}

Solve separable ODE:

y = 3 \frac{3 x ^{2}}{2} + 21

y = 3 \frac{3 x ^{2}}{2} + 21

(2 - x^{3}) y^{^{'}} - 3 x^{2} y = 0

\frac{d y}{d x} = (\frac{y}{x})

u^{^{'}} = 2 e^{7 x - H (x)}

2 (x^{2} y - y) d y - (2 x y^{2} - 2 x) d x = 0

\frac{d x}{d t} = x^{2} + \frac{1}{49}

What is the solution for (dy)/(dx)= x/(y^2),y(2)=3 ?
The solution for (dy)/(dx)= x/(y^2),y(2)=3 is y=\sqrt[3]{(3x^2)/2+21}