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Popular >

y^'=ye^{-x}

Solution

y^{^{'}} = y e^{- x}

Solution

y = e^{- e^{- x} + c_{1}}

Solution steps

y^{'} (x) = y e^{- x}

Solve separable ODE:

y = e^{- e^{- x} + c_{1}}

y = e^{- e^{- x} + c_{1}}

Popular Examples

(dx)/(dy)=k(150-2x)

\frac{d x}{d y} = k (150 - 2 x)

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(ln (y))^{2} \frac{d y}{d x} = x^{2} y, y (1) = e^{2}

x(xz)+(xz)^2dx-x^2(xdz+zdx)=0

x (x z) + (x z)^{2} d x - x^{2} (x d z + z d x) = 0

2xydx=(2-x^2)dy

2 x y d x = (2 - x^{2}) d y

(uy+y)(udy+ydu)-uydy=0

(u y + y) (u d y + y d u) - u y d y = 0

Frequently Asked Questions (FAQ)

What is the solution for y^'=ye^{-x} ?
The solution for y^'=ye^{-x} is y=e^{-e^{-x}+c_{1}}