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Popular >

y^'=2xy-4x

Solution

y^{^{'}} = 2 x y - 4 x

Solution

y = e^{x^{2} + c_{1}} + 2

Solution steps

y^{'} (x) = 2 x y - 4 x

Solve separable ODE:

y = e^{x^{2} + c_{1}} + 2

y = e^{x^{2} + c_{1}} + 2

Popular Examples

y^'sec(x)=8y^2,y(pi/2)= 1/3

y^{^{'}} sec (x) = 8 y^{2}, y (\frac{π}{2}) = \frac{1}{3}

(dP)/(dt)=7sqrt(Pt),P(1)=7

\frac{d P}{d t} = 7 Pt, P (1) = 7

(dy)/(dx)=6\sqrt[4]{xy}

(dy)/(dt)=cos^2(y)

\frac{d y}{d t} = cos^{2} (y)

(dy)/(dx)y=(1/3)(x^2+2)^{3/2}

\frac{d y}{d x} y = (\frac{1}{3}) (x^{2} + 2)^{\frac{3}{2}}

Frequently Asked Questions (FAQ)

What is the solution for y^'=2xy-4x ?
The solution for y^'=2xy-4x is y=e^{x^2+c_{1}}+2