What is the solution for (dy)/(dx)+5y=20,y(0)=2 ?

The solution for (dy)/(dx)+5y=20,y(0)=2 is y=-2e^{-5x}+4

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(dy)/(dx)+5y=20,y(0)=2

\frac{d y}{d x} + 5 y = 20, y (0) = 2

y = - 2 e^{- 5 x} + 4

Solution steps

\frac{d y}{d x} + 5 y = 20

Solve separable ODE:

y = - 2 e^{- 5 x} + 4

y = - 2 e^{- 5 x} + 4

\frac{d y}{d x} = \frac{- x + x y ^{2}}{y + x ^{2} y}

y^{^{'}} = x^{2} - 2 x^{2} y

1 - y^{2} (d x) - 1 + x^{2} (d y) = 0

1 = \frac{5}{3} y + \frac{d y}{d x}

\frac{d y}{d t} + 5 t y = e^{t} y

What is the solution for (dy)/(dx)+5y=20,y(0)=2 ?
The solution for (dy)/(dx)+5y=20,y(0)=2 is y=-2e^{-5x}+4