What is (\partial)/(\partial x)((y-2)(arctan(x))) ?

The answer to (\partial)/(\partial x)((y-2)(arctan(x))) is (y-2)/(x^2+1)

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(\partial)/(\partial x)((y-2)(arctan(x)))

\frac{\partial}{\partial x} ((y - 2) (arctan (x)))

\frac{y - 2}{x ^{2} + 1}

Solution steps

\frac{\partial}{\partial x} ((y - 2) (arctan (x)))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= (y - 2) \frac{\partial}{\partial x} (arctan (x))

Apply the common derivative:

\frac{\partial}{\partial x} (arctan (x)) = \frac{1}{x ^{2} + 1}

= (y - 2) \frac{1}{x ^{2} + 1}

Simplify

(y - 2) \frac{1}{x ^{2} + 1} : \frac{y - 2}{x ^{2} + 1}

= \frac{y - 2}{x ^{2} + 1}

\frac{d}{d x} (\frac{csc ( x )}{2 ^{x}})

x \to 0 lim (\frac{x ^{2} - 2 x}{x})

\frac{d}{d x} (- sin (5 x))

\int \frac{4 + x ^{2}}{x ^{2}} d x

\int_{0}^{2 π} sin^{2} (8 x) d x

What is (\partial)/(\partial x)((y-2)(arctan(x))) ?
The answer to (\partial)/(\partial x)((y-2)(arctan(x))) is (y-2)/(x^2+1)