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Popular >

u^'=x^2\H(x)

Solution

u^{^{'}} = x^{2} H (x)

Solution

u (x) = \int x^{2} H (x) d x

Solution steps

u^{'} (x) = x^{2} H (x)

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

u (x) = \int x^{2} H (x) d x

u (x) = \int x^{2} H (x) d x

Popular Examples

(dy)/(dx)=-(3x+3xy^2)/(yx^2+2y)

\frac{d y}{d x} = - \frac{3 x + 3 x y ^{2}}{y x ^{2} + 2 y}

((dy))/((dx))=(2x+10)*e^{-y},y(0)=0

\frac{( d y )}{( d x )} = (2 x + 10) \cdot e^{- y}, y (0) = 0

g=(dv)/(dt)+v^2k

g = \frac{d v}{d t} + v^{2} k

y^'-2y=2y^{1/2}

y^{^{'}} - 2 y = 2 y^{\frac{1}{2}}

y^2y^'=2(t+ty^3)e^{t^2}

y^{2} y^{^{'}} = 2 (t + t y^{3}) e^{t^{2}}

Frequently Asked Questions (FAQ)

What is the solution for u^'=x^2\H(x) ?
The solution for u^'=x^2\H(x) is u(x)=integral of x^2\H(x)