What is the solution for (dy)/(dx)=x(y-1)-2y+2 ?

The solution for (dy)/(dx)=x(y-1)-2y+2 is y=e^{(x^2)/2-2x+c_{1}}+1

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(dy)/(dx)=x(y-1)-2y+2

\frac{d y}{d x} = x (y - 1) - 2 y + 2

y = e^{\frac{x ^{2}}{2} - 2 x + c_{1}} + 1

Solution steps

\frac{d y}{d x} = x (y - 1) - 2 y + 2

Solve separable ODE:

y = e^{\frac{x ^{2}}{2} - 2 x + c_{1}} + 1

y = e^{\frac{x ^{2}}{2} - 2 x + c_{1}} + 1

y^{^{'}} = y \frac{7 ( t ^{2} - 1 )}{t ( t - 3 ) ( t - 4 )}, y (7) = 3

y^{^{'}} = 25 + y^{2}, y (0) = 5 tan (5 x)

\frac{d y}{d x} = \frac{x ^{3} y ^{3}}{x + 3}

y^{^{'}} - 2 x y = 3 x

\frac{d y}{d x} = \frac{1}{x} (y^{2} + y), y (1) = 1

What is the solution for (dy)/(dx)=x(y-1)-2y+2 ?
The solution for (dy)/(dx)=x(y-1)-2y+2 is y=e^{(x^2)/2-2x+c_{1}}+1