What is the solution for (dy)/(dx)=(x+1)/(y^2),y(1)=0 ?

The solution for (dy)/(dx)=(x+1)/(y^2),y(1)=0 is y=\sqrt[3]{(3x^2)/2+3x-9/2}

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(dy)/(dx)=(x+1)/(y^2),y(1)=0

\frac{d y}{d x} = \frac{x + 1}{y ^{2}}, y (1) = 0

Solution steps

\frac{d y}{d x} = \frac{x + 1}{y ^{2}}

Solve separable ODE:

y^{^{'}} csc (t) = \frac{- y ^{21}}{20}

\frac{d p}{d t} = 0.0017 p (1 - \frac{p}{6200})

2 x (y + 1) - y^{^{'}} y = 0

\frac{d y}{d x} + y^{2} cos (x) = 0

y^{^{'}} = \frac{x ^{2} - 1}{2 x + x y}

What is the solution for (dy)/(dx)=(x+1)/(y^2),y(1)=0 ?
The solution for (dy)/(dx)=(x+1)/(y^2),y(1)=0 is y=\sqrt[3]{(3x^2)/2+3x-9/2}