What is the solution for (x^2-1)(dy)/(dx)=y^2-1,y(2)=2 ?

The solution for (x^2-1)(dy)/(dx)=y^2-1,y(2)=2 is y=x

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(x^2-1)(dy)/(dx)=y^2-1,y(2)=2

(x^{2} - 1) \frac{d y}{d x} = y^{2} - 1, y (2) = 2

y = x

Solution steps

(x^{2} - 1) \frac{d y}{d x} = y^{2} - 1

Solve separable ODE:

y = x

y = x

\frac{d y}{d t} = k y + n

x \frac{d y}{d x} = e^{2 y + x}

y^{^{'}} = \frac{( 5 x ^{2} - 1 )}{5 + 4 y}

y^{^{'}} - 5 y = 15

y^{^{'}} + 4 y = 1.4, y (0) = c e^{- 4 x} + 0.35, y (0) = 2

What is the solution for (x^2-1)(dy)/(dx)=y^2-1,y(2)=2 ?
The solution for (x^2-1)(dy)/(dx)=y^2-1,y(2)=2 is y=x