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Popular >

y^'+2xy=3x

Solution

y^{^{'}} + 2 x y = 3 x

Solution

y = \frac{e ^{- x^{2} + c_{1}}}{2} + \frac{3}{2}

Solution steps

y^{'} (x) + 2 x y = 3 x

Solve separable ODE:

y = \frac{e ^{- x^{2} + c_{1}}}{2} + \frac{3}{2}

y = \frac{e ^{- x^{2} + c_{1}}}{2} + \frac{3}{2}

Popular Examples

(dy)/(dx)=x^4(y-3),y(0)=9

\frac{d y}{d x} = x^{4} (y - 3), y (0) = 9

(dy)/(dx)+(2xy)/(x^2-1)= x/(x^2-1)

\frac{d y}{d x} + \frac{2 x y}{x ^{2} - 1} = \frac{x}{x ^{2} - 1}

(dy)/(dx)=-8/4 x^3y^5

\frac{d y}{d x} = - \frac{8}{4} x^{3} y^{5}

(ydy)/(xdx)=(sqrt(y^2+1))/(sqrt(x^2+1))

\frac{y d y}{x d x} = \frac{y ^{2} + 1}{x ^{2} + 1}

[k*f(x)]=k*f^'(x)

[k \cdot f (x)] = k \cdot f^{^{'}} (x)

Frequently Asked Questions (FAQ)

What is the solution for y^'+2xy=3x ?
The solution for y^'+2xy=3x is y=(e^{-x^2+c_{1}})/2+3/2