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Popular >

y^'=5y,y(0)=10

Solution

y^{^{'}} = 5 y, y (0) = 10

Solution

y = 10 e^{5 t}

Solution steps

y^{'} (t) = 5 y

Solve separable ODE:

y = 10 e^{5 t}

y = 10 e^{5 t}

Popular Examples

(dy)/(dx)=((3x^2+4x+2)/(2(y-1)))

\frac{d y}{d x} = (\frac{3 x ^{2} + 4 x + 2}{2 ( y - 1 )})

y(dy)/(dx)=5x(y^2+5)^2

y \frac{d y}{d x} = 5 x (y^{2} + 5)^{2}

(dy)/(dx)= x/(y+x^2y),y(0)=2

\frac{d y}{d x} = \frac{x}{y + x ^{2} y}, y (0) = 2

y^'+y=y(te^{t^2}+1)

y^{^{'}} + y = y (t e^{t^{2}} + 1)

\frac{d v}{d t} + 2 v = 0

Frequently Asked Questions (FAQ)

What is the solution for y^'=5y,y(0)=10 ?
The solution for y^'=5y,y(0)=10 is y=10e^{5t}