What is the solution for (dQ)/(dx)=15-3 Q/(400) ?

The solution for (dQ)/(dx)=15-3 Q/(400) is Q=-(e^{(-3x-c_{1})/(400)})/3+2000

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(dQ)/(dx)=15-3 Q/(400)

\frac{d Q}{d x} = 15 - 3 \frac{Q}{400}

Q = - \frac{e ^{\frac{- 3 x - c _{1}}{400}}}{3} + 2000

Solution steps

\frac{d Q}{d x} = 15 - 3 \frac{Q}{400}

Solve separable ODE:

Q = - \frac{e ^{\frac{- 3 x - c _{1}}{400}}}{3} + 2000

Q = - \frac{e ^{\frac{- 3 x - c _{1}}{400}}}{3} + 2000

e^{t} y^{^{'}} = (1 + y^{2}) t

x^{2} y^{^{'}} = y^{2}, y (1) = - 1

x y d y = (1 + y^{2}) (1 - x) d x

y^{^{'}} = \frac{x}{y}, y (0) = - 3

\frac{d}{d t} (H (t)) = 4 - 0.5 H (t), H (0) = 0

What is the solution for (dQ)/(dx)=15-3 Q/(400) ?
The solution for (dQ)/(dx)=15-3 Q/(400) is Q=-(e^{(-3x-c_{1})/(400)})/3+2000