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Popular >

y^'=-1-y^2

Solution

y^{^{'}} = - 1 - y^{2}

Solution

y = tan (- t - c_{1})

Solution steps

y^{'} (t) = - 1 - y^{2}

Solve separable ODE:

y = tan (- t - c_{1})

y = tan (- t - c_{1})

Popular Examples

(dy)/(dt)= t/(y^2sqrt(1+t))

\frac{d y}{d t} = \frac{t}{y ^{2} 1 + t}

y^{^{'}} - 4 y = 12

(dy)/(dx)=(2y(1-4y))/(x-1)

\frac{d y}{d x} = \frac{2 y ( 1 - 4 y )}{x - 1}

y^{^{'}} = x y - 4 x

(a^3y)/(ax^3)-21(dy)/(dx)-20y=0

\frac{a ^{3} y}{a x ^{3}} - 21 \frac{d y}{d x} - 20 y = 0

Frequently Asked Questions (FAQ)

What is the solution for y^'=-1-y^2 ?
The solution for y^'=-1-y^2 is y=tan(-t-c_{1})