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Popular >

y^'=yln(y)

Solution

y^{^{'}} = y ln (y)

Solution

y = e^{e^{t + c_{1}}}

Solution steps

y^{'} (t) = y ln (y)

Solve separable ODE:

y = e^{e^{t + c_{1}}}

y = e^{e^{t + c_{1}}}

Popular Examples

y^'=((2-e^x))/((3+2y))

y^{^{'}} = \frac{( 2 - e ^{x} )}{( 3 + 2 y )}

(dP)/(dt)=sqrt(Pt),P(1)=6

\frac{d P}{d t} = Pt, P (1) = 6

(dy)/(dx)=(sqrt(x^3))/(2y),y(0)=-4

\frac{d y}{d x} = \frac{x ^{3}}{2 y}, y (0) = - 4

y^{^{'}} + y = - 2

sqrt(x)(dy)/(dx)=e^{10y+sqrt(x)},x>0

x \frac{d y}{d x} = e^{10 y + x}, x > 0

Frequently Asked Questions (FAQ)

What is the solution for y^'=yln(y) ?
The solution for y^'=yln(y) is y=e^{e^{t+c_{1}}}