What is the solution for (dy)/(dx)=(x^3)/(2y^2) ?

The solution for (dy)/(dx)=(x^3)/(2y^2) is y=(\sqrt[3]{c_{1}+3x^4})/2

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(dy)/(dx)=(x^3)/(2y^2)

\frac{d y}{d x} = \frac{x ^{3}}{2 y ^{2}}

Solution steps

\frac{d y}{d x} = \frac{x ^{3}}{2 y ^{2}}

Solve separable ODE:

\frac{d y}{d x} = - \frac{0.1}{cos ( y )}, y (0) = \frac{π}{2}

\frac{d v}{d t} = \frac{t + 2}{v}

\frac{d y}{d x} = \frac{y ( 2 - 3 x )}{x ( 1 - 3 y )}

\frac{d y}{d x} = 8 x y^{2}, y (0) = 1

\frac{d y}{d x} = 2 x^{2} y^{2}

What is the solution for (dy)/(dx)=(x^3)/(2y^2) ?
The solution for (dy)/(dx)=(x^3)/(2y^2) is y=(\sqrt[3]{c_{1}+3x^4})/2