What is the solution for (dy)/(dx)=-4/4 x^8y^4 ?

The solution for (dy)/(dx)=-4/4 x^8y^4 is y=-\sqrt[3]{3/(-x^9+c_{1)}}

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(dy)/(dx)=-4/4 x^8y^4

\frac{d y}{d x} = - \frac{4}{4} x^{8} y^{4}

Solution steps

\frac{d y}{d x} = - \frac{4}{4} x^{8} y^{4}

Solve separable ODE:

\frac{d y}{d t} + 2 (t + 1) y^{2} = 0, y (0) = - \frac{1}{8}

y^{^{'}} = \frac{ln ( x )}{x y}, y (1) = 2

- (\frac{d x}{d y}) = \frac{( x ^{2} y ^{2} )}{( 1 + x )}

\frac{d y}{d t} = e^{- y} (2 t - 4), y (2) = 0

\frac{d h}{d t} = 1 - 0.5 h

What is the solution for (dy)/(dx)=-4/4 x^8y^4 ?
The solution for (dy)/(dx)=-4/4 x^8y^4 is y=-\sqrt[3]{3/(-x^9+c_{1)}}