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Popular >

y^'=-1/y

Solution

y^{^{'}} = - \frac{1}{y}

Solution

y = - 2 t + c_{1}, y = - - 2 t + c_{1}

Solution steps

y^{'} (t) = - \frac{1}{y}

Solve separable ODE:

y = - 2 t + c_{1}, y = - - 2 t + c_{1}

y = - 2 t + c_{1}, y = - - 2 t + c_{1}

Popular Examples

(dy)/(dx)= y/(sqrt(1+x^2))

\frac{d y}{d x} = \frac{y}{1 + x ^{2}}

[1+t^2](dy)/(dt)=1+y^2

[1 + t^{2}] \frac{d y}{d t} = 1 + y^{2}

y^'=x^2y,y(0)=1

y^{^{'}} = x^{2} y, y (0) = 1

y^3y^'+4xy^4=8x

y^{3} y^{^{'}} + 4 x y^{4} = 8 x

2xy^3+3x^2y^2(dy)/(dx)=0

2 x y^{3} + 3 x^{2} y^{2} \frac{d y}{d x} = 0

Frequently Asked Questions (FAQ)

What is the solution for y^'=-1/y ?
The solution for y^'=-1/y is y=sqrt(-2t+c_{1)},y=-sqrt(-2t+c_{1)}