What is the sum from n=1 to infinity of 3/(n^{5/3)} ?

The sum from n=1 to infinity of 3/(n^{5/3)} is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of 3/(n^{5/3)}

n = 1 \sum \infty \frac{3}{n ^{\frac{5}{3}}}

converges

Solution steps

n = 1 \sum \infty \frac{3}{n ^{\frac{5}{3}}}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 3 \cdot n = 1 \sum \infty \frac{1}{n ^{\frac{5}{3}}}

Apply p-Series Test:

converges

= 3 converges

= converges

∣ x ∣ + 3

f (x) = sec (x), (\frac{π}{3}, 2)

\frac{\partial}{\partial y} (sinh (2 x + 3 y))

\frac{55.9}{t ^{2} - 0.31 t + 11.2}

\frac{\partial}{\partial x} (- 3 x^{2} + 28)

What is the sum from n=1 to infinity of 3/(n^{5/3)} ?
The sum from n=1 to infinity of 3/(n^{5/3)} is converges