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Popular >

(x+1)dx= 1/(-y^2)dy

Solution

(x + 1) d x = \frac{1}{- y ^{2}} d y

Solution

y = - \frac{2}{- x ^{2} - 2 x + c _{1}}

Solution steps

(x + 1) d x = \frac{1}{- y ^{2}} d y

Solve separable ODE:

y = - \frac{2}{- x ^{2} - 2 x + c _{1}}

y = - \frac{2}{- x ^{2} - 2 x + c _{1}}

Popular Examples

y^'=((y^2+1))/((x^2+1))

y^{^{'}} = \frac{( y ^{2} + 1 )}{( x ^{2} + 1 )}

(2 t - 1) y^{^{'}} - 4 y = 0

(dp)/(dt)+2tp=p+8t-4

\frac{d p}{d t} + 2 tp = p + 8 t - 4

f(x)f^'(x)=xx^3-xx^2-6xx

f (x) f^{^{'}} (x) = x x^{3} - x x^{2} - 6 xx

f^'(x)=f(x)^{-1}(x)

f^{^{'}} (x) = f (x)^{- 1} (x)

Frequently Asked Questions (FAQ)

What is the solution for (x+1)dx= 1/(-y^2)dy ?
The solution for (x+1)dx= 1/(-y^2)dy is y=-2/(-x^2-2x+c_{1)}