What is the solution for e^x((dy)/(dx))=1+y^2 ?

The solution for e^x((dy)/(dx))=1+y^2 is y=tan(-1/(e^x)+c_{1})

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e^x((dy)/(dx))=1+y^2

e^{x} (\frac{d y}{d x}) = 1 + y^{2}

y = tan (- \frac{1}{e ^{x}} + c_{1})

Solution steps

e^{x} (\frac{d y}{d x}) = 1 + y^{2}

Solve separable ODE:

y = tan (- \frac{1}{e ^{x}} + c_{1})

y = tan (- \frac{1}{e ^{x}} + c_{1})

\frac{d y}{d x} = 4 x 36 - y^{2}

\frac{d y}{d t} = \frac{- t}{y}, y = 4

y = sin (2) (ln (x^{2} - 3 x + 2)) y^{^{'}}

\frac{d v}{d t} = 90 - \frac{4}{100} v, v = 0, t = 0

y^{^{'}} - 2 y + a = 0

What is the solution for e^x((dy)/(dx))=1+y^2 ?
The solution for e^x((dy)/(dx))=1+y^2 is y=tan(-1/(e^x)+c_{1})