What is the solution for (dP)/(dt)=1P-2P^2 ?

The solution for (dP)/(dt)=1P-2P^2 is P=-(e^{t+c_{1}})/(1-2e^{t+c_{1)}}

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(dP)/(dt)=1P-2P^2

\frac{d P}{d t} = 1 P - 2 P^{2}

P = - \frac{e ^{t + c_{1}}}{1 - 2 e ^{t + c_{1}}}

Solution steps

\frac{d P}{d t} = 1 P - 2 P^{2}

Solve separable ODE:

P = - \frac{e ^{t + c_{1}}}{1 - 2 e ^{t + c_{1}}}

P = - \frac{e ^{t + c_{1}}}{1 - 2 e ^{t + c_{1}}}

\frac{d y}{d x} + 7 y = y^{2} + 12

6 y^{^{'}} - 3 e^{2 x} y = 0, y (0) = 4

y^{^{'}} \cdot sin^{2} (x) = cos (x) (1 - 3 y)

x^{3} y d x + 9 d y = 0

y^{^{'}} = 2 y^{2} \cdot e^{- x^{2}}, y (0) = 1

What is the solution for (dP)/(dt)=1P-2P^2 ?
The solution for (dP)/(dt)=1P-2P^2 is P=-(e^{t+c_{1}})/(1-2e^{t+c_{1)}}