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Popular >

y^'=2x-3xy

Solution

y^{^{'}} = 2 x - 3 x y

Solution

y = \frac{e ^{\frac{- 3 x ^{2} + c _{1}}{2}}}{3} + \frac{2}{3}

Solution steps

y^{'} (x) = 2 x - 3 x y

Solve separable ODE:

y = \frac{e ^{\frac{- 3 x ^{2} + c _{1}}{2}}}{3} + \frac{2}{3}

y = \frac{e ^{\frac{- 3 x ^{2} + c _{1}}{2}}}{3} + \frac{2}{3}

Popular Examples

ln (y^{^{'}}) = y

y y^{^{'}} - x y^{2} + x = 0

(1+x^2)(dy)/(dx)=xtan(y)

(1 + x^{2}) \frac{d y}{d x} = x tan (y)

e^{-y}sin(x)-(dy)/(dx)cos^2(x)=0

e^{- y} sin (x) - \frac{d y}{d x} cos^{2} (x) = 0

(dy)/(dx)=(17xy)/((ln(y))^6)

\frac{d y}{d x} = \frac{17 x y}{( ln ( y ) ) ^{6}}

Frequently Asked Questions (FAQ)

What is the solution for y^'=2x-3xy ?
The solution for y^'=2x-3xy is y=(e^{(-3x^2+c_{1})/2})/(3)+2/3