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Popular >

x^'+cx=0

Solution

x^{^{'}} + c x = 0

Solution

x = e^{- c t + c_{1}}

Solution steps

x^{'} (t) + c x (t) = 0

Solve separable ODE:

x = e^{- c t + c_{1}}

x = e^{- c t + c_{1}}

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Frequently Asked Questions (FAQ)

What is the solution for x^'+cx=0 ?
The solution for x^'+cx=0 is x=e^{-ct+c_{1}}