What is the solution for (t^2-26t+133)(dy)/(dt)=y ?

The solution for (t^2-26t+133)(dy)/(dt)=y is y=(c_{1}\sqrt[12]{t-19})/(\sqrt[12]{t-7)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(t^2-26t+133)(dy)/(dt)=y

(t^{2} - 26 t + 133) \frac{d y}{d t} = y

Solution steps

(t^{2} - 26 t + 133) \frac{d y}{d t} = y

Solve separable ODE:

y^{^{'}} = (2 y - 1)^{3}

y^{^{'}} = - \frac{3}{7} x^{6} y^{5}

e^{x} \frac{d y}{d x} - y^{2} (x + 1) = 0

\frac{d y}{d x} 2 x^{3} y + 3 x y^{3} = 0

(\frac{x}{x ^{2} + y ^{2}}) d x - (\frac{y}{x ^{2} + y ^{2}}) d y = 0

What is the solution for (t^2-26t+133)(dy)/(dt)=y ?
The solution for (t^2-26t+133)(dy)/(dt)=y is y=(c_{1}\sqrt[12]{t-19})/(\sqrt[12]{t-7)}