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Popular >

xy*y^'=y-1

Solution

x y \cdot y^{^{'}} = y - 1

Solution

y = W (x c_{1}) + 1

Solution steps

x y \cdot y^{'} (x) = y - 1

Solve separable ODE:

y = W (x c_{1}) + 1

y = W (x c_{1}) + 1

Popular Examples

xe^{x^2}+yy^'=0,y(0)=1

x e^{x^{2}} + y y^{^{'}} = 0, y (0) = 1

(dy)/(dx)=-(0.8)/(cos(y)),y(0)= pi/4

\frac{d y}{d x} = - \frac{0.8}{cos ( y )}, y (0) = \frac{π}{4}

\frac{1}{1 - 2 y} d y = x d x

(dx)/(y^2)=(dy)/(x^2)

\frac{d x}{y ^{2}} = \frac{d y}{x ^{2}}

x^'=-(15x)/(1000),x(0)=15

x^{^{'}} = - \frac{15 x}{1000}, x (0) = 15

Frequently Asked Questions (FAQ)

What is the solution for xy*y^'=y-1 ?
The solution for xy*y^'=y-1 is y=\W(xc_{1})+1