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Popular >

(2x+3)y^'=y+4

Solution

(2 x + 3) y^{^{'}} = y + 4

Solution

y = c_{1} 2 x + 3 - 4

Solution steps

(2 x + 3) y^{'} (x) = y + 4

Solve separable ODE:

y = c_{1} 2 x + 3 - 4

y = c_{1} 2 x + 3 - 4

Popular Examples

y^'=(-(3y^2+1)x)/(x^2+1),y(0)=1

y^{^{'}} = \frac{- ( 3 y ^{2} + 1 ) x}{x ^{2} + 1}, y (0) = 1

y^'=(240-6y)/(180)

y^{^{'}} = \frac{240 - 6 y}{180}

(dy)/(dt)=ty^2+2y^2,y(0)=1

\frac{d y}{d t} = t y^{2} + 2 y^{2}, y (0) = 1

sin(2x)dx+cos(9y)dy=0

sin (2 x) d x + cos (9 y) d y = 0

y \cdot y^{^{'}} = x

Frequently Asked Questions (FAQ)

What is the solution for (2x+3)y^'=y+4 ?
The solution for (2x+3)y^'=y+4 is y=c_{1}sqrt(2x+3)-4