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Popular >

8y^{''}-32y=0

Solution

8 y^{^{''}} - 32 y = 0

Solution

y = c_{1} e^{2 t} + c_{2} e^{- 2 t}

Solution steps

8 y^{''} (t) - 32 y = 0

Solve linear ODE:

y = c_{1} e^{2 t} + c_{2} e^{- 2 t}

y = c_{1} e^{2 t} + c_{2} e^{- 2 t}

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Frequently Asked Questions (FAQ)

What is the solution for 8y^{''}-32y=0 ?
The solution for 8y^{''}-32y=0 is y=c_{1}e^{2t}+c_{2}e^{-2t}