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Popular >

y^'+32 y/x =0

Solution

y^{^{'}} + 32 \frac{y}{x} = 0

Solution

y = \frac{c _{1}}{x ^{32}}

Solution steps

y^{'} (x) + 32 \frac{y}{x} = 0

Solve separable ODE:

y = \frac{c _{1}}{x ^{32}}

y = \frac{c _{1}}{x ^{32}}

Popular Examples

y^'=(xysin(x))/(y+1),y(0)=1

y^{^{'}} = \frac{x y sin ( x )}{y + 1}, y (0) = 1

x^{^{'}} = 1 - 3 x + x^{2}

u^'=3e^{8x-\H(x)}

u^{^{'}} = 3 e^{8 x - H (x)}

y^'=((3x^2+4x-4))/(2y-4),y(1)=3

y^{^{'}} = \frac{( 3 x ^{2} + 4 x - 4 )}{2 y - 4}, y (1) = 3

(y/(sec^2(x)))(dy)/(dx)=2tan(x)+1

(\frac{y}{sec ^{2} ( x )}) \frac{d y}{d x} = 2 tan (x) + 1

Frequently Asked Questions (FAQ)

What is the solution for y^'+32 y/x =0 ?
The solution for y^'+32 y/x =0 is y=(c_{1})/(x^{32)}