What is the solution for y^'= 1/(3y^2(x^2+1)) ?

The solution for y^'= 1/(3y^2(x^2+1)) is y=\sqrt[3]{arctan(x)+c_{1}}

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y^'= 1/(3y^2(x^2+1))

y^{^{'}} = \frac{1}{3 y ^{2} ( x ^{2} + 1 )}

Solution steps

y^{'} (x) = \frac{1}{3 y ^{2} ( x ^{2} + 1 )}

Solve separable ODE:

y^{^{'}} = \frac{3 x ^{2}}{2 y - 4}

y^{^{'}} + 100 y = 5

\frac{d y}{d x} + 6 x^{2} y = 5 x^{2}, y (0) = 2

\frac{d y}{d x} = sin (x) (1 - cos (x)) (y^{2} - 4)

\frac{d y}{d x} = \frac{( x ^{2} + 1 )}{2 - 2 y}

What is the solution for y^'= 1/(3y^2(x^2+1)) ?
The solution for y^'= 1/(3y^2(x^2+1)) is y=\sqrt[3]{arctan(x)+c_{1}}