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Popular >

-y^'-9y=0

Solution

- y^{^{'}} - 9 y = 0

Solution

y = e^{- 9 t + c_{1}}

Solution steps

- y^{'} (t) - 9 y = 0

Solve separable ODE:

y = e^{- 9 t + c_{1}}

y = e^{- 9 t + c_{1}}

Popular Examples

(dy)/(dx)=x^2(y-2),y(0)=9

\frac{d y}{d x} = x^{2} (y - 2), y (0) = 9

(dy)/(dx)=x^2(y-2),y(0)=8

\frac{d y}{d x} = x^{2} (y - 2), y (0) = 8

y^'=(x-4)/(y-8)

y^{^{'}} = \frac{x - 4}{y - 8}

xdz+zdx=(x^2-x^2z^2)/(3x^2z)

x d z + z d x = \frac{x ^{2} - x ^{2} z ^{2}}{3 x ^{2} z}

y^{^{'}} = 4 x (1 + y)^{2}

Frequently Asked Questions (FAQ)

What is the solution for -y^'-9y=0 ?
The solution for -y^'-9y=0 is y=e^{-9t+c_{1}}