What is the solution for dy(y+x^2y)=2xdx ?

The solution for dy(y+x^2y)=2xdx is y=sqrt(2ln(x^2+1)+c_{1)},y=-sqrt(2ln(x^2+1)+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

dy(y+x^2y)=2xdx

d y (y + x^{2} y) = 2 x d x

y = 2 ln (x^{2} + 1) + c_{1}, y = - 2 ln (x^{2} + 1) + c_{1}

Solution steps

d y (y + x^{2} y) = 2 x d x

Solve separable ODE:

y = 2 ln (x^{2} + 1) + c_{1}, y = - 2 ln (x^{2} + 1) + c_{1}

y = 2 ln (x^{2} + 1) + c_{1}, y = - 2 ln (x^{2} + 1) + c_{1}

y^{^{'}} = x y^{3} (1 + x^{2})^{- \frac{1}{2}}, y (0) = - 1

\frac{d y}{d x} = \frac{- 0.7}{cos ( y )}, y (0) = \frac{π}{2}

\frac{y - y ^{^{'}}}{x ^{2}} = 0

x^{^{'}} + x^{2} = 0

y^{^{'}} = \frac{24 ln ^{2} ( x )}{x e ^{y}}

What is the solution for dy(y+x^2y)=2xdx ?
The solution for dy(y+x^2y)=2xdx is y=sqrt(2ln(x^2+1)+c_{1)},y=-sqrt(2ln(x^2+1)+c_{1)}