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Popular >

2y=3-xy^'

Solution

2 y = 3 - x y^{^{'}}

Solution

y = - \frac{c _{1}}{2 x ^{2}} + \frac{3}{2}

Solution steps

2 y = 3 - x y^{'} (x)

Solve separable ODE:

y = - \frac{c _{1}}{2 x ^{2}} + \frac{3}{2}

y = - \frac{c _{1}}{2 x ^{2}} + \frac{3}{2}

Popular Examples

\frac{1}{y} d y = - \frac{1}{x} d x

e^yy^'=((ln(t))^2)/t ,y(1)=ln(10)

e^{y} y^{^{'}} = \frac{( ln ( t ) ) ^{2}}{t}, y (1) = ln (10)

(3xcos(3x)+sin(3x)-3)dx+(2y+5)dy=0

(3 x cos (3 x) + sin (3 x) - 3) d x + (2 y + 5) d y = 0

sin(2x)dy-e^ydx=0

sin (2 x) d y - e^{y} d x = 0

y^'=9y^{-2},y(0)=3

y^{^{'}} = 9 y^{- 2}, y (0) = 3

Frequently Asked Questions (FAQ)

What is the solution for 2y=3-xy^' ?
The solution for 2y=3-xy^' is y=-(c_{1})/(2x^2)+3/2