What is the tangent of sqrt(x)(1.1) ?

The tangent of sqrt(x)(1.1) is y=(0.55)/(sqrt(a_{0))}x+(11sqrt(a_{0)})/(20)

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tangent of sqrt(x)(1.1)

tangent of

x (1.1)

y = \frac{0.55}{a _{0}} x + \frac{11 a _{0}}{20}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, a_{0} \cdot 1.1)

Find the slope of

y = x 1.1 : \frac{d y}{d x} = \frac{0.55}{x}

Compute the slope of

y = x 1.1

x = a_{0} : m = \frac{0.55}{a _{0}}

Find the line with slope m=

\frac{0.55}{a _{0}}

and passing through

(a_{0}, a_{0} 1.1) : y = \frac{0.55}{a _{0}} x + \frac{11 a _{0}}{20}

y = \frac{0.55}{a _{0}} x + \frac{11 a _{0}}{20}

\frac{\partial}{\partial x} (2 x - 3 y)

\frac{d}{d x} (1 + 3^{2 x})

\int \frac{4}{6 + 4 x} d x

\int_{- r}^{r} (r^{2} - x^{2}) d x

y^{^{'}} = 0.21 - \frac{y}{1700}

What is the tangent of sqrt(x)(1.1) ?
The tangent of sqrt(x)(1.1) is y=(0.55)/(sqrt(a_{0))}x+(11sqrt(a_{0)})/(20)