ty^'+y=5

الحلّ

t y^{^{'}} + y = 5

y = - \frac{c _{1}}{t} + 5

خطوات الحلّ

t y^{'} (t) + y = 5

Solve separable ODE:

y = - \frac{c _{1}}{t} + 5

y = - \frac{c _{1}}{t} + 5

\frac{d y}{d t} = - 2 (t + 1) y^{2}, y (0) = - \frac{1}{8}

(y e^{x} + x y e^{x}) d x = - (x e^{x} + 2) d y

\frac{d y}{d x} = \frac{e ^{x}}{e ^{y}}, y (0) = 0

(1 + x^{2}) y^{^{'}} = x^{2} e^{2 y}

y^{^{'}} = - 0.004 y + 50, y (0) = 0