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Popular >

y^'=1-0.4y

Solution

y^{^{'}} = 1 - 0.4 y

Solution

y = - \frac{5 e ^{\frac{- 2 t - c _{1}}{5}}}{2} + \frac{5}{2}

Solution steps

y^{'} (t) = 1 - 0.4 y

Solve separable ODE:

y = - \frac{5 e ^{\frac{- 2 t - c _{1}}{5}}}{2} + \frac{5}{2}

y = - \frac{5 e ^{\frac{- 2 t - c _{1}}{5}}}{2} + \frac{5}{2}

Popular Examples

y^'=(8x^3+1)/(3y^2)

y^{^{'}} = \frac{8 x ^{3} + 1}{3 y ^{2}}

(dy)/(dx)=-(0.9)/(cos(y)),y(0)= pi/3

\frac{d y}{d x} = - \frac{0.9}{cos ( y )}, y (0) = \frac{π}{3}

y^'=t(1+y/4),y(1)=2.4

y^{^{'}} = t (1 + \frac{y}{4}), y (1) = 2.4

(dy)/(dx)=(5sqrt(x))/(e^y)

\frac{d y}{d x} = \frac{5 x}{e ^{y}}

\frac{d v}{d t} = - 2 v

Frequently Asked Questions (FAQ)

What is the solution for y^'=1-0.4y ?
The solution for y^'=1-0.4y is y=-(5e^{(-2t-c_{1})/5})/(2)+5/2