What is area y=4-x^2,y=x^2-4x-2 ?

The answer to area y=4-x^2,y=x^2-4x-2 is 64/3

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area y=4-x^2,y=x^2-4x-2

area

y = 4 - x^{2}, y = x^{2} - 4 x - 2

\frac{64}{3}

Decimal Notation

21.33333 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{3} 4 - x^{2} - (x^{2} - 4 x - 2) d x

Solve

\int_{- 1}^{3} 4 - x^{2} - (x^{2} - 4 x - 2) d x : \frac{64}{3}

The area is:

= \frac{64}{3}

n = 2 \sum \infty \frac{3 ^{n}}{1 0 ^{n}}

\frac{1}{1 + sin ( π \cdot x )}

\int \frac{k}{x ln ( x )} d x

\frac{d}{d x} (\frac{x}{x ^{2} - 8})