What is the solution for (dy)/(dx)y=(6x-4)^3 ?

The solution for (dy)/(dx)y=(6x-4)^3 is y=sqrt(1/12 (6x-4)^4+c_{1)},y=-sqrt(1/12 (6x-4)^4+c_{1)}

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(dy)/(dx)y=(6x-4)^3

\frac{d y}{d x} y = (6 x - 4)^{3}

y = \frac{1}{12} (6 x - 4)^{4} + c_{1}, y = - \frac{1}{12} (6 x - 4)^{4} + c_{1}

Solution steps

\frac{d y}{d x} y = (6 x - 4)^{3}

Solve separable ODE:

y = \frac{1}{12} (6 x - 4)^{4} + c_{1}, y = - \frac{1}{12} (6 x - 4)^{4} + c_{1}

y = \frac{1}{12} (6 x - 4)^{4} + c_{1}, y = - \frac{1}{12} (6 x - 4)^{4} + c_{1}

2 = \frac{1}{10} y + (100 \cdot 1 0^{- 3}) y^{^{'}}

\frac{d y}{d x} = x^{3} y^{2} - x y^{2}

\frac{d y}{d t} = 2 t y^{2} + 3 t^{2} y^{2}

\frac{d}{d t} (v (t) e^{k t}) = g e^{k t}

d x = x^{7} y d y

What is the solution for (dy)/(dx)y=(6x-4)^3 ?
The solution for (dy)/(dx)y=(6x-4)^3 is y=sqrt(1/12 (6x-4)^4+c_{1)},y=-sqrt(1/12 (6x-4)^4+c_{1)}