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Popular >

y^'-2xy=x,y(0)=0

Solution

y^{^{'}} - 2 x y = x, y (0) = 0

Solution

y = \frac{e ^{x^{2}}}{2} - \frac{1}{2}

Solution steps

y^{'} (x) - 2 x y = x

Solve separable ODE:

y = \frac{e ^{x^{2}}}{2} - \frac{1}{2}

y = \frac{e ^{x^{2}}}{2} - \frac{1}{2}

Popular Examples

integral of 2^{2x+1}

\int 2^{2 x + 1} d x

tangent of f(x)=2-3x^2,\at x=1 tangent of

f (x) = 2 - 3 x^{2}, at x = 1

derivative of (x^3^2)

\frac{d}{d x} ((x^{3})^{2})

integral of 1/(ax+bx^2)

\int \frac{1}{a x + b x ^{2}} d x

limit as x approaches-1 of (x^2-1)/(x+1)

x \to - 1 lim (\frac{x ^{2} - 1}{x + 1})

Frequently Asked Questions (FAQ)

What is the solution for y^'-2xy=x,y(0)=0 ?
The solution for y^'-2xy=x,y(0)=0 is y=(e^{x^2})/2-1/2