What is the solution for (dy)/(dx)5x^2-4y^2=16 ?

The solution for (dy)/(dx)5x^2-4y^2=16 is y=2tan(-8/(5x)+c_{1})

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(dy)/(dx)5x^2-4y^2=16

\frac{d y}{d x} 5 x^{2} - 4 y^{2} = 16

y = 2 tan (- \frac{8}{5 x} + c_{1})

Solution steps

\frac{d y}{d x} 5 x^{2} - 4 y^{2} = 16

Solve separable ODE:

y = 2 tan (- \frac{8}{5 x} + c_{1})

y = 2 tan (- \frac{8}{5 x} + c_{1})

\frac{d y}{d x} y = e^{x + y}

(x y + y^{2}) y^{^{'}} = x^{2} + x y, y (1) = 0

y^{^{'}} = x^{2} + y^{2} + x^{2} y^{2} + 1

a x^{^{'}} + b x = 0, x (0) = e^{r t}

(4 x^{5} - 16 x^{3} - 2 x) (1 - y^{2}) - 2 y (x^{2} - 4) y^{^{'}} = 0

What is the solution for (dy)/(dx)5x^2-4y^2=16 ?
The solution for (dy)/(dx)5x^2-4y^2=16 is y=2tan(-8/(5x)+c_{1})