What is the solution for (1-y^2)dx=xydy ?

The solution for (1-y^2)dx=xydy is y=(sqrt(c_{1)+x^2})/x ,y=-(sqrt(c_{1)+x^2})/x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(1-y^2)dx=xydy

(1 - y^{2}) d x = x y d y

y = \frac{c _{1} + x ^{2}}{x}, y = - \frac{c _{1} + x ^{2}}{x}

Solution steps

(1 - y^{2}) d x = x y d y

Solve separable ODE:

y = \frac{c _{1} + x ^{2}}{x}, y = - \frac{c _{1} + x ^{2}}{x}

y = \frac{c _{1} + x ^{2}}{x}, y = - \frac{c _{1} + x ^{2}}{x}

\frac{1}{y} \frac{d y}{d x} = x^{- 1} + x^{2}

\frac{d y}{d x} = y^{2} + 1, y (0) = 0

\frac{d p}{d t} = 2 pt, p (1) = 6

y^{^{'}} + 3 y = 13, y (0) = 0

y^{^{'}} + x^{2} y = 0, y (0) = 2

What is the solution for (1-y^2)dx=xydy ?
The solution for (1-y^2)dx=xydy is y=(sqrt(c_{1)+x^2})/x ,y=-(sqrt(c_{1)+x^2})/x