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Popular >

x^'=e^x 1/t

Solution

x^{^{'}} = e^{x} \frac{1}{t}

Solution

x = - ln (- ln (t) - c_{1})

Solution steps

x^{'} (t) = e^{x} \frac{1}{t}

Solve separable ODE:

x = - ln (- ln (t) - c_{1})

x = - ln (- ln (t) - c_{1})

Popular Examples

(3x-5)dx+(y+b)dy=0

(3 x - 5) d x + (y + b) d y = 0

(dy)/(dx)=3y^{2/3},y(2)=0

\frac{d y}{d x} = 3 y^{\frac{2}{3}}, y (2) = 0

y y^{^{'}} = e^{2 x} + 1

(dy)/(dx)=-4e^{2x}y^2,y(0)=1

\frac{d y}{d x} = - 4 e^{2 x} y^{2}, y (0) = 1

y=x^3e^{-2x}cos(3x)(dy)/(dx)

y = x^{3} e^{- 2 x} cos (3 x) \frac{d y}{d x}

Frequently Asked Questions (FAQ)

What is the solution for x^'=e^x 1/t ?
The solution for x^'=e^x 1/t is x=-ln(-ln(t)-c_{1})