What is the solution for x^'=0.075x-9000 ?

The solution for x^'=0.075x-9000 is x=(e^{0.075t+c_{1}})/(0.075)+(9000)/(0.075)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^'=0.075x-9000

x^{^{'}} = 0.075 x - 9000

x = \frac{e ^{0.075 t + c_{1}}}{0.075} + \frac{9000}{0.075}

Solution steps

x^{'} (t) = 0.075 x - 9000

Solve separable ODE:

x = \frac{e ^{0.075 t + c_{1}}}{0.075} + \frac{9000}{0.075}

x = \frac{e ^{0.075 t + c_{1}}}{0.075} + \frac{9000}{0.075}

(3 y^{2} - 8 x^{- 1} y) d x + (3 x y - 8) d y = 0

cos (8 y) d y = - sin (2 x) d x

(t^{2} + 1) y^{^{'}} - \frac{t + 2}{y} = 0

\frac{d y}{d x} = 0.0175 - 0.3821 \cdot y

e^{y} = y^{^{'}}

What is the solution for x^'=0.075x-9000 ?
The solution for x^'=0.075x-9000 is x=(e^{0.075t+c_{1}})/(0.075)+(9000)/(0.075)