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Popular >

y^'=e^{(x-2y)}

Solution

y^{^{'}} = e^{(x - 2 y)}

Solution

y = \frac{ln ( 2 e ^{x} + c _{1} )}{2}

Solution steps

y^{'} (x) = e^{(x - 2 y)}

Solve separable ODE:

y = \frac{ln ( 2 e ^{x} + c _{1} )}{2}

y = \frac{ln ( 2 e ^{x} + c _{1} )}{2}

Popular Examples

2 y y^{^{'}} = x e^{x}

f^'(x)= 1/(sqrt(1-(f(x))^2)),f(x)(g(x))=x

f^{^{'}} (x) = \frac{1}{1 - ( f ( x ) ) ^{2}}, f (x) (g (x)) = x

y^'=xe^{5x-3y},y(0)=2

y^{^{'}} = x e^{5 x - 3 y}, y (0) = 2

(dx)/(dt)=2sqrt(x)

\frac{d x}{d t} = 2 x

x(dy)/(dx)-y=y^2

x \frac{d y}{d x} - y = y^{2}

Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{(x-2y)} ?
The solution for y^'=e^{(x-2y)} is y=(ln(2e^x+c_{1}))/2