What is the solution for (dy}{dx}=(\frac{y+1)/x) ?

The solution for (dy}{dx}=(\frac{y+1)/x) is y=c_{1}x-1

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(dy}{dx}=(\frac{y+1)/x)

\frac{d y}{d x} = (\frac{y + 1}{x})

y = c_{1} x - 1

Solution steps

\frac{d y}{d x} = (\frac{y + 1}{x})

Solve separable ODE:

y = c_{1} x - 1

y = c_{1} x - 1

\frac{d y}{d x} = y (10000 - 50 x)

81 x^{2} + 2 y \cdot \frac{d y}{d x} = 0

y^{^{'}} + \frac{1}{2} (x - 2) y^{2} = 0, y (6) = \frac{1}{10}

y^{^{'}} - 5 y = 0, y (0) = 3

x d y - (y + 17) d x = 0

What is the solution for (dy}{dx}=(\frac{y+1)/x) ?
The solution for (dy}{dx}=(\frac{y+1)/x) is y=c_{1}x-1