What is the solution for 3(y^2+1)dx+2xydy=0 ?

The solution for 3(y^2+1)dx+2xydy=0 is y=sqrt((c_{1)-x^3)/(x^3)},y=-sqrt((c_{1)-x^3)/(x^3)}

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3(y^2+1)dx+2xydy=0

3 (y^{2} + 1) d x + 2 x y d y = 0

y = \frac{c _{1} - x ^{3}}{x ^{3}}, y = - \frac{c _{1} - x ^{3}}{x ^{3}}

Solution steps

3 (y^{2} + 1) d x + 2 x y d y = 0

Solve separable ODE:

y = \frac{c _{1} - x ^{3}}{x ^{3}}, y = - \frac{c _{1} - x ^{3}}{x ^{3}}

y = \frac{c _{1} - x ^{3}}{x ^{3}}, y = - \frac{c _{1} - x ^{3}}{x ^{3}}

1 x \frac{d y}{d x} + y = \frac{5}{y ^{2}}

x^{^{'}} = 3 x + 3 x

(x - y^{2} x) d x = - (y - x^{2} y) d y

\frac{d y}{d x} + 4 y = 8, y (0) = 0

y^{^{'}} = 0.05 y - k, y (0) = 400000, y (15) = 0

What is the solution for 3(y^2+1)dx+2xydy=0 ?
The solution for 3(y^2+1)dx+2xydy=0 is y=sqrt((c_{1)-x^3)/(x^3)},y=-sqrt((c_{1)-x^3)/(x^3)}