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Popular >

y^'=ysin(3x+1)

Solution

y^{^{'}} = y sin (3 x + 1)

Solution

y = e^{- \frac{1}{3} c o s (3 x + 1) + c_{1}}

Solution steps

y^{'} (x) = y sin (3 x + 1)

Solve separable ODE:

y = e^{- \frac{1}{3} c o s (3 x + 1) + c_{1}}

y = e^{- \frac{1}{3} c o s (3 x + 1) + c_{1}}

Popular Examples

y^'=(sin(x)e^{x+2y})/y

y^{^{'}} = \frac{sin ( x ) e ^{x + 2 y}}{y}

(dN)/(dt)= 3/2 N

\frac{d N}{d t} = \frac{3}{2} N

(dy}{dx}-y/x =-\frac{y^2)/x

\frac{d y}{d x} - \frac{y}{x} = - \frac{y ^{2}}{x}

sqrt(x)(dy)/(dx)=e^{6y+sqrt(x)}

x \frac{d y}{d x} = e^{6 y + x}

(dt)/(dx)=(ln(x))/(x^2t)

\frac{d t}{d x} = \frac{ln ( x )}{x ^{2} t}

Frequently Asked Questions (FAQ)

What is the solution for y^'=ysin(3x+1) ?
The solution for y^'=ysin(3x+1) is y=e^{-1/3 cos(3x+1)+c_{1}}