en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=(4x^3)/(y^2)

Solution

y^{^{'}} = \frac{4 x ^{3}}{y ^{2}}

Solution

Solution steps

y^{'} (x) = \frac{4 x ^{3}}{y ^{2}}

Solve separable ODE:

Popular Examples

(dy)/(dx)=-3/2 x^7y^8

\frac{d y}{d x} = - \frac{3}{2} x^{7} y^{8}

y^'=-0.02y+3,y(0)=0

y^{^{'}} = - 0.02 y + 3, y (0) = 0

(dy)/(dx)=(xy^3)/((1+x^2)^{-1/2)},y=1

\frac{d y}{d x} = \frac{x y ^{3}}{( 1 + x ^{2} ) ^{- \frac{1}{2}}}, y = 1

(dy)/(dx)=sqrt(yx),y(1)=3

\frac{d y}{d x} = y x, y (1) = 3

2sin(x)-y^2(dy)/(dx)=0

2 sin (x) - y^{2} \frac{d y}{d x} = 0

Frequently Asked Questions (FAQ)

What is the solution for y^'=(4x^3)/(y^2) ?
The solution for y^'=(4x^3)/(y^2) is y=\sqrt[3]{3x^4+c_{1}}