What is the solution for (dy)/(dx)=(y+1)/(x+1) ?

The solution for (dy)/(dx)=(y+1)/(x+1) is y=e^{c_{1}}x+e^{c_{1}}-1

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(dy)/(dx)=(y+1)/(x+1)

\frac{d y}{d x} = \frac{y + 1}{x + 1}

y = e^{c_{1}} x + e^{c_{1}} - 1

Solution steps

\frac{d y}{d x} = \frac{y + 1}{x + 1}

Solve separable ODE:

y = e^{c_{1}} x + e^{c_{1}} - 1

y = e^{c_{1}} x + e^{c_{1}} - 1

\frac{d x}{d t} = 80 - \frac{x}{100}, x = 4000, t = 0

\frac{d y}{d x} = x (y - 2)

(t^{2} - 6 t + 5) \frac{d y}{d t} = y

\frac{d y}{d t} = \frac{3 t ^{2} + 4 t + 2}{2 ( y - 1 )}

2 y + 3 + (2 x - 4) y^{^{'}} = 0

What is the solution for (dy)/(dx)=(y+1)/(x+1) ?
The solution for (dy)/(dx)=(y+1)/(x+1) is y=e^{c_{1}}x+e^{c_{1}}-1