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Popular >

x^'-5x=25

Solution

x^{^{'}} - 5 x = 25

Solution

x = e^{5 t + c_{1}} - 5

Solution steps

x^{'} (t) - 5 x = 25

Solve separable ODE:

x = e^{5 t + c_{1}} - 5

x = e^{5 t + c_{1}} - 5

Popular Examples

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\frac{d}{d θ} (r (θ)) = \frac{r ( θ ) ^{2}}{θ}, r (1) = 2

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\frac{d y}{d t} + 7 y = 6, y (0) = 0

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x f^{^{'}} (x) = (f (x))^{2}

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(dy)/(dx)=8xy-12x^2y

\frac{d y}{d x} = 8 x y - 12 x^{2} y

Frequently Asked Questions (FAQ)

What is the solution for x^'-5x=25 ?
The solution for x^'-5x=25 is x=e^{5t+c_{1}}-5